-[3z-(7z+2)]=2+(3z+6)

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Solution for -[3z-(7z+2)]=2+(3z+6) equation:


Simplifying
-1[3z + -1(7z + 2)] = 2 + (3z + 6)

Reorder the terms:
-1[3z + -1(2 + 7z)] = 2 + (3z + 6)
-1[3z + (2 * -1 + 7z * -1)] = 2 + (3z + 6)
-1[3z + (-2 + -7z)] = 2 + (3z + 6)

Reorder the terms:
-1[-2 + 3z + -7z] = 2 + (3z + 6)

Combine like terms: 3z + -7z = -4z
-1[-2 + -4z] = 2 + (3z + 6)
[-2 * -1 + -4z * -1] = 2 + (3z + 6)
[2 + 4z] = 2 + (3z + 6)

Reorder the terms:
2 + 4z = 2 + (6 + 3z)

Remove parenthesis around (6 + 3z)
2 + 4z = 2 + 6 + 3z

Combine like terms: 2 + 6 = 8
2 + 4z = 8 + 3z

Solving
2 + 4z = 8 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
2 + 4z + -3z = 8 + 3z + -3z

Combine like terms: 4z + -3z = 1z
2 + 1z = 8 + 3z + -3z

Combine like terms: 3z + -3z = 0
2 + 1z = 8 + 0
2 + 1z = 8

Add '-2' to each side of the equation.
2 + -2 + 1z = 8 + -2

Combine like terms: 2 + -2 = 0
0 + 1z = 8 + -2
1z = 8 + -2

Combine like terms: 8 + -2 = 6
1z = 6

Divide each side by '1'.
z = 6

Simplifying
z = 6

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